That's not going to work. Multiples of 5 end in 5 or 0. With three numbers, one of those would have to repeat.
2, 4, 6
They are multiples of 1, 3 and 9.
Well, honey, the common multiples of 4, 8, and 16 are numbers that all three can divide evenly into. So, the first few common multiples would be 16, 32, 48, and so on. Just keep adding 16 to get more of those bad boys. Happy counting!
Because it's not even. Multiples of 6 have to also be multiples of two, that is, even numbers.
The infinite set of numbers which are multiples of three. The infinite set of numbers which are multiples of three. The infinite set of numbers which are multiples of three. The infinite set of numbers which are multiples of three.
Any numbers that are not multiples of three.
900
Multiples of 6 cannot, by definition, be prime numbers!
vhghghghvv
There are 898 three-digit even numbers. Nine of them are multiples of 55. That leaves 889 * * * * * There are 450 three-digit even numbers and 17 of them are multiples of 55. So that leaves 433.
All multiples of 514, which is an infinite number. The first three numbers are 514, 1028, 1542.
Infinity. Numbers never end!
42 of them.
33 and 1/3%
300600900are some
450