That's not going to work. Multiples of 5 end in 5 or 0. With three numbers, one of those would have to repeat.
2, 4, 6
They are multiples of 1, 3 and 9.
The common multiples of 4, 8, and 16 are numbers that are divisible by all three of these numbers. To find the common multiples, we first list the multiples of each number: 4 (4, 8, 12, 16, 20, ...), 8 (8, 16, 24, ...), and 16 (16, 32, 48, ...). The common multiples of 4, 8, and 16 are the numbers that appear in all three lists, which are multiples of the least common multiple of 4, 8, and 16, which is 16. Therefore, the common multiples are numbers that are multiples of 16 (16, 32, 48, ...).
All of those numbers have an infinite amount of multiples.
The infinite set of numbers which are multiples of three. The infinite set of numbers which are multiples of three. The infinite set of numbers which are multiples of three. The infinite set of numbers which are multiples of three.
Any numbers that are not multiples of three.
900
Multiples of 6 cannot, by definition, be prime numbers!
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There are 898 three-digit even numbers. Nine of them are multiples of 55. That leaves 889 * * * * * There are 450 three-digit even numbers and 17 of them are multiples of 55. So that leaves 433.
All multiples of 514, which is an infinite number. The first three numbers are 514, 1028, 1542.
Infinity. Numbers never end!
42 of them.
33 and 1/3%
300600900are some
450