The factor pairs of 68 are:
68 x 1 = 68
34 x 2 = 68
17 x 4 = 68
Therefore, the list of positive integer factors of 68 are: 1, 2, 4, 17, 34, 68.
The factor pairs of 57 are 3x19 and 1x57
The factor pairs of 343 are (343,1) and (49,7)
20 has 3 factor pairs. Pairs are (1,20), (2,10) and (9,9)
The factor pairs of 12 are (12,1), (6,2), and (4,3) The factor pairs of 18 are (18,1), (9,2), and (6,3)
The factor pairs of 111 are 1x111, 11x10. These are in order.
1*68=68,2*34=68,and 17*4=68
(68, 1) (34, 2) (17, 4)
(68,1)(34,2)(17,4)
(1, 68) (2, 34) (4, 17)
68 pairs .
I prefer to show my divisors as factor pairs, to make it less likely to forget any. 1 and 68 2 and 34 4 and 17 That is all of it.
To express 68 as a product of 2 factors, we need to find all pairs of numbers that multiply to 68. The pairs are: 1 and 68, 2 and 34, 4 and 17, and 17 and 4. These pairs give us the following expressions: 1 x 68, 2 x 34, 4 x 17, and 17 x 4.
Yes. Factor pairs are always repeated across pairs since factor pairs are certain kinds of pairs.
the factor pairs are 1x35 & 5x7
The factor pairs of 28 are :28,114,27,4
Sixteen factor pairs.
68 is.