factors: 1, 3, 5, 9, 15, 27, 45, 81, 135, 243, 405, 1215
prime factors: 3(5), 5
3 x 3 x 3 x 3 x 3 x 5 = 1215
There is more than one possible answer. The prime factors of 16 are 2, 2, 2, and 2. It has four prime factors, but only one distinct prime factor. The prime factors of 24 are 2, 2, 2, and 3. It has four prime factors, but only two distinct prime factors. The prime factors of 36 are 2, 2, 3, and 3. It has four prime factors, but only two distinct prime factors. The prime factors of 40 are 2, 2, 2, and 5. It has four prime factors, but only two distinct prime factors. The prime factors of 54 are 2, 3, 3, and 3. It has four prime factors, but only two distinct prime factors. The prime factors of 56 are 2, 2, 2, and 7. It has four prime factors, but only two distinct prime factors. The prime factors of 60 are 2, 2, 3, and 5. It has four prime factors, but only three distinct prime factors. The prime factors of 81 are 3, 3, 3, and 3. It has four prime factors, but only one distinct prime factor. The prime factors of 84 are 2, 2, 3, and 7. It has four prime factors, but only three distinct prime factors. The prime factors of 88 are 2, 2, 2, and 11. It has four prime factors, but only two distinct prime factors. The prime factors of 90 are 2, 3, 3, and 5. It has four prime factors, but only three distinct prime factors.
The prime factors of 336 are: 2,3,7
To find the highest common factor (HCF) of 81, 243, and 1215, we first need to find the prime factorization of each number. The prime factorization of 81 is 3^4, 243 is 3^5, and 1215 is 3^5 * 5. To find the HCF, we look for the highest power of each prime factor that appears in all the numbers. In this case, the highest power of 3 that appears in all three numbers is 3^4, so the HCF of 81, 243, and 1215 is 81.
The factors of 1993 are: 1 1993 The prime factors are: 1993 is a prime number.
1215, 405,243,135,81,45,27,15,9,5,3,1
35 x 5 = 1215
To find fractions equivalent to 1215, we need to divide 1215 by a common factor. The prime factorization of 1215 is 3 x 3 x 3 x 3 x 3 x 3 x 5. So, any fraction where both the numerator and denominator are multiples of these prime factors will be equivalent to 1215. For example, 2430/2, 405/3, and 135/5 are all equivalent fractions to 1215.
1, 3, 5, 9, 15, 25, 27, 45, 75, 81, 135, 225, 243, 405, 675, 1215, 2025, 6075 3 and 5 are prime.
The answer is. 5x3x3x3x3x3
35 times 5
3 x 3 x 3 x 3 x 3 x 5 = 1215
To express 1215 as a fraction in simplest form, we can write it as 1215/1. Since 1215 and 1 share no common factors other than 1, the fraction 1215/1 is already in its simplest form.
They are: 1,3,9 for 1215 and 18
Prime factors are factors that are also prime numbers.
There is more than one possible answer. The prime factors of 16 are 2, 2, 2, and 2. It has four prime factors, but only one distinct prime factor. The prime factors of 24 are 2, 2, 2, and 3. It has four prime factors, but only two distinct prime factors. The prime factors of 36 are 2, 2, 3, and 3. It has four prime factors, but only two distinct prime factors. The prime factors of 40 are 2, 2, 2, and 5. It has four prime factors, but only two distinct prime factors. The prime factors of 54 are 2, 3, 3, and 3. It has four prime factors, but only two distinct prime factors. The prime factors of 56 are 2, 2, 2, and 7. It has four prime factors, but only two distinct prime factors. The prime factors of 60 are 2, 2, 3, and 5. It has four prime factors, but only three distinct prime factors. The prime factors of 81 are 3, 3, 3, and 3. It has four prime factors, but only one distinct prime factor. The prime factors of 84 are 2, 2, 3, and 7. It has four prime factors, but only three distinct prime factors. The prime factors of 88 are 2, 2, 2, and 11. It has four prime factors, but only two distinct prime factors. The prime factors of 90 are 2, 3, 3, and 5. It has four prime factors, but only three distinct prime factors.
The prime factors of 336 are: 2,3,7