To find the highest common factor (HCF) of 81, 243, and 1215, we first need to find the prime factorization of each number. The prime factorization of 81 is 3^4, 243 is 3^5, and 1215 is 3^5 * 5. To find the HCF, we look for the highest power of each prime factor that appears in all the numbers. In this case, the highest power of 3 that appears in all three numbers is 3^4, so the HCF of 81, 243, and 1215 is 81.
factors: 1, 3, 5, 9, 15, 27, 45, 81, 135, 243, 405, 1215prime factors: 3(5), 5
All factors of 243 are: -243, -81, -27, -9, -3, -1, 1, 3, 9, 27, 81, and 243.
The positive integer factors of 243 are 1, 3, 9, 27, 81, and 243 The factor pairs of 243 are (1, 243), (3, 81), and (9, 27).
The least common factor of two numbers is the smallest positive integer that both numbers can be evenly divided by. In this case, the factors of 81 are 1, 3, 9, 27, and 81, while the factors of 243 are 1, 3, 9, 27, 81, and 243. The least common factor of 81 and 243 is 81, as it is the smallest factor that both numbers share.
The factors of 243 are: 1 3 9 27 81 243
1, 3, 5, 9, 15, 27, 45, 81, 135, 243, 405, 1215.
5 x 243 9 x 135 15 x 81 for example
1215 over 10 simplified = 243/2
factors: 1, 3, 5, 9, 15, 27, 45, 81, 135, 243, 405, 1215prime factors: 3(5), 5
1, 3, 9, 27, 81, 243, -1, -3, -9, -27, -81, -243
The LCM is: 243
All factors of 243 are: -243, -81, -27, -9, -3, -1, 1, 3, 9, 27, 81, and 243.
It is: 81
The positive integer factors of 243 are 1, 3, 9, 27, 81, and 243 The factor pairs of 243 are (1, 243), (3, 81), and (9, 27).
Yes, 243 is divisible by 1, 3, 9, 27, 81, 243.
The least common factor of two numbers is the smallest positive integer that both numbers can be evenly divided by. In this case, the factors of 81 are 1, 3, 9, 27, and 81, while the factors of 243 are 1, 3, 9, 27, 81, and 243. The least common factor of 81 and 243 is 81, as it is the smallest factor that both numbers share.
The next number is 243, because 81x3=243.