To find the highest common factor (HCF) of 81, 243, and 1215, we first need to find the prime factorization of each number. The prime factorization of 81 is 3^4, 243 is 3^5, and 1215 is 3^5 * 5. To find the HCF, we look for the highest power of each prime factor that appears in all the numbers. In this case, the highest power of 3 that appears in all three numbers is 3^4, so the HCF of 81, 243, and 1215 is 81.
factors: 1, 3, 5, 9, 15, 27, 45, 81, 135, 243, 405, 1215prime factors: 3(5), 5
All factors of 243 are: -243, -81, -27, -9, -3, -1, 1, 3, 9, 27, 81, and 243.
The positive integer factors of 243 are 1, 3, 9, 27, 81, and 243 The factor pairs of 243 are (1, 243), (3, 81), and (9, 27).
The factors of 81 are 1, 3, 9, 27, and 81. The factors of 243 are 1, 3, 9, 27, 81, and 243. The common factors of 81 and 243 are 1, 3, 9, 27, and 81. Therefore, the least common factor (the smallest common factor) is 1.
The factors of 243 are: 1 3 9 27 81 243
1, 3, 5, 9, 15, 27, 45, 81, 135, 243, 405, 1215.
5 x 243 9 x 135 15 x 81 for example
1215 over 10 simplified = 243/2
It is: 81 which is the HCF
Oh, dude, let me do the math real quick... Alright, so 5 can go into 1215 like 243 times. That's a lot of fives squeezing into that big ol' number. So, yeah, 243 times, give or take a high five.
factors: 1, 3, 5, 9, 15, 27, 45, 81, 135, 243, 405, 1215prime factors: 3(5), 5
1, 3, 9, 27, 81, 243, -1, -3, -9, -27, -81, -243
The LCM is: 243
All factors of 243 are: -243, -81, -27, -9, -3, -1, 1, 3, 9, 27, 81, and 243.
It is: 81
The positive integer factors of 243 are 1, 3, 9, 27, 81, and 243 The factor pairs of 243 are (1, 243), (3, 81), and (9, 27).
Yes, 243 is divisible by 1, 3, 9, 27, 81, 243.