1,3,7,21,49,147 1, & 147 is not the only factors of 147 because 147 is not prime
They are 3 and 7
The prime factors of 147 are 3, 7 and 7. From those we can create all the other factors ... (3 x 7) and (7 x 7) which are 21 and 49. 1 is a factor of every number, and every number is a factor of itself. So all the factors of 147 are 1, 3, 7, 7, 21, 49 and 147
No, it is not a prime. 147=3*7*7.
There is no such thing as a 'highest common multiple', but the least common multiple or LCM can be found using prime numbers. The LCM of the given numbers is the product of all different prime factors to their greatest power. If there are no exponents, the greatest power of the prime factors is 1 and each different prime factor is used in the multiplication:prime factors of 210 are 2 x 3 x 5 x 7;prime factors of 147 are 3 x 72;the LCM of 210 and 147 is 2 x 3 x 5 x 72 = 1470
factors of 147 = 1, 3, 7, 21, 49, and 147. prime factors of 147: 3, 7
1,3,7,21,49,147 1, & 147 is not the only factors of 147 because 147 is not prime
As a product of its prime factors: 3*7*7 = 147
As a product of its prime factors: 3*7*7 = 147
As a product of its prime factors: 3*7*7 = 147
3 x 7 x 7 = 147
147 is composite because it has more than two factors.
1, 3, 7, 21, 49, 147 3 and 7 are prime.
73 is prime, so it is just 1 and 73.
As a product of its prime factors: 3*7*7 = 147
Since there are no common prime factors, the GCF of 22 and 147 is 1.
The numbers that multiply to get 147 are its prime factors. To find the prime factors of 147, we start by dividing it by the smallest prime number, which is 3. 147 รท 3 = 49. Then, we divide 49 by 7 (7 is also a prime number), which gives us 7. Therefore, the numbers that multiply to get 147 are 3, 7, and 7.