Q: What are the factors of 49x2 minus 7x minus 72?

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49x2 - 84x + 36 = (7x - 6)(7x - 6) or (7x - 6)2

(7x + 8)(7x - 8)

The required equation is: -7x = 63

(x + 1)(x - 8)

32= -3 - 7x 32 + 3 = - 7x 35= - 7x 35/7 = -x 5 = -x -5= x

Related questions

(7x + 8)(7x - 9)

49x2 - 84x + 36 = (7x - 6)(7x - 6) or (7x - 6)2

(7x + 8)(7x - 9)

There are no real factors.Complex factors are (7x + 9yi) and (7x - 9yi) where i is the imaginary square root of -1.

(7x + 8)(7x - 8)

(7x - 22)(7x + 22)

64y3 - 216x3 factors to -8(3x - 2y)(9x2 + 6xy + 4y2) 49x2 - 16y2 factors to (7x - 4y)(7x + 4y)

(3b + 7x)(3b + 7x) or (3b + 7x)2

Minus 61 (-61)

49x2 - 56x + 16 = (7x - 4)2 so yes, it can be a perfect square.

49x2+28x+4 = (7x+2)(7x+2) when factored

I assume that is (7x-2)^2 = 16 (7x-2)(7x-2) = 16 49x2 -28x +4 = 16 49x2-28x-12=0 use quadratic formula x = ( -b +/-sqrt(b2-4ac) ) /2a x = -2/7