I assume that is
(7x-2)^2 = 16
(7x-2)(7x-2) = 16
49x2 -28x +4 = 16
49x2-28x-12=0
use quadratic formula x = ( -b +/-sqrt(b2-4ac) ) /2a
x = -2/7
Either: (7x + 4)(x + 4) = 7x2 + 32x + 16 or: (7x - 4)(x - 4) = 7x2 - 32x + 16
Solve using the quadratic formula
32 + x = 259 + x = 25x = 25 - 9x = 16
16
(b-4) squared
14x2-7x2-16 7x2-16 (this can't be simplified any more)
Either: (7x + 4)(x + 4) = 7x2 + 32x + 16 or: (7x - 4)(x - 4) = 7x2 - 32x + 16
Solve using the quadratic formula
x^(2)-16=0 Take the -16 over to the other side of the equal sign, the -16 will turn +16. x^(2)=16 Then take the squared root of both sides. x=4
32 + x = 259 + x = 25x = 25 - 9x = 16
16 squared equals 256.
16
(b-4) squared
4
By factoring. q2 + 16q = 0 q (q + 16) = 0 Now, either q = 0, or q + 16 = 0. Solve those two equations to get the solution.
4i where i = sqrt (-1) 4i x 4 i = 16 i squared = -16
4 squared is 4 x 4 which equals 16.