The factor pairs of 25 are 1 x 25 and 5 x 5
factor pairs: 1*375, 3*125,5*75,15*25
If pairs of factors separate independently of other pairs of factors, you are dealing with the: Law of independent assortment
Factors go in pairs; prime factors are listed least to greatest. 2, 3 and 11
Factors: 1, 3, 9, 27. Pairs: (1,27);(3,9).
The factor pairs of 50 are (1, 50), (2, 25), and (5, 10). These pairs are formed by finding two numbers that multiply together to give 50. The factors of 50 are all the numbers that can evenly divide into 50 without leaving a remainder.
(1,25) (5,5)
The factor pairs of 125 are 1 x 125 and 5 x 25
the pairs are 1 x 25 5 x 5
factor pairs: 1*375, 3*125,5*75,15*25
To find how many pairs of numbers multiply to 325, we first determine the factors of 325. The prime factorization of 325 is (5^2 \times 13). The factors of 325 are 1, 5, 13, 25, 65, and 325, leading to the pairs: (1, 325), (5, 65), and (13, 25). Thus, there are three distinct pairs of factors that multiply to give 325.
1 is the only common factor of 25 and 26. 25 and 26 are "relatively prime," as are all pairs of consecutive integers.
If pairs of factors separate independently of other pairs of factors, you are dealing with the: Law of independent assortment
Factors of 6 : 1, 2, 3, 6 Factors of 25 : 1, 5, 25 Factors of 55, 1, 5, 11, 55 Common factor pairs = 5 (from 25 and 55) LCM = Product of all numbers divide by the common factors LCM = (6 x 25 x 55) / (5) = 1650
Factors of 50 are 1, 2, 5, 10, 25 and 50. If we are restricted to choose only two factors then elements of following pairs on multiplication give 50: {1, 50}, {2, 25} and {5, 10}.
Factors of 50 in pairs: 1 x 50, 2 x 25, 5 x 10.
3 pairs
These are the factor pairs:1750,1875,2350,5250,7175,10125,1470,2550,35