1,1.5,2,2.25,3,4,4.5,6,9
there's 9.....because it's a perfect square, it's normal 5 pairs of multiples(to make your required 10), is reduced to 4 1/2. One of its multiples is used with itself to form 9(3). Since two different integers cannot be squared and still equal the same number, you cannot reach 10. 9 is as close as you can get.
9,18,27,36,45,54,63,72,81,90
The first six multiples of 3 are 3, 6, 9, 12, 15, and 18. They are the products of 3 and the nonzero integers 1, 2, 3, 4, 5, and 6.
9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, 108
The first two multiples are 9 and 8.
The first 5 multiples of 9 are 9, 18, 27, 36, and 45. For them to be common, they need to be compared to another set of multiples.
They are the first three multiples of LCM(5, 9), that is, the first three multiples of 45.
Take the first number. Add it to itself. Keep adding that number to the total three more times. The first five nonzero multiples of 9 are 9, 18, 27, 36, and 45. Put another way, let each number equal x. The first five nonzero multiples of x are 1x, 2x, 3x, 4x and 5x.
9,18,27,36,45,54,63,72,81,90
The first 10 multiples of 3 are: 3, 6, 9, 12, 15, 18, 21, 24, 27, and 30.
1 3 9
That's an infinite list.
The first six multiples of 3 are 3, 6, 9, 12, 15, and 18. They are the products of 3 and the nonzero integers 1, 2, 3, 4, 5, and 6.
9, 18, 27, 36, 45, 54, 63, 72, 81, 90.
3,6,9,12,15,18,21,24,27,30 and so on but these are the first ten multiples of three
9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, 108
The first 10 multiples of 3 are: 3, 6, 9, 12, 15, 18, 21, 24, 27, and 30.
9, 18, 27, 36, 45, 54, 63, 72, 81, 90.