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1,1.5,2,2.25,3,4,4.5,6,9

there's 9.....because it's a perfect square, it's normal 5 pairs of multiples(to make your required 10), is reduced to 4 1/2. One of its multiples is used with itself to form 9(3). Since two different integers cannot be squared and still equal the same number, you cannot reach 10. 9 is as close as you can get.

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Q: What are the first ten nonzero multiples of 9?
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