The first six multiples of 3 are 3, 6, 9, 12, 15, and 18. They are the products of 3 and the nonzero integers 1, 2, 3, 4, 5, and 6.
1,1.5,2,2.25,3,4,4.5,6,9there's 9.....because it's a perfect square, it's normal 5 pairs of multiples(to make your required 10), is reduced to 4 1/2. One of its multiples is used with itself to form 9(3). Since two different integers cannot be squared and still equal the same number, you cannot reach 10. 9 is as close as you can get.
The first two multiples are 9 and 8.
The first 5 multiples of 9 are 9, 18, 27, 36, and 45. For them to be common, they need to be compared to another set of multiples.
You can't have common multiples if they have nothing to be in common with however the first 3 multiples of 9 are 9,18 and 27 Think of just your times tables when finding out Multiples to find the first 5 multiples just count by 9's until you have said 5 numbers and Bingo
They are the first three multiples of LCM(5, 9), that is, the first three multiples of 45.
Take the first number. Add it to itself. Keep adding that number to the total three more times. The first five nonzero multiples of 9 are 9, 18, 27, 36, and 45. Put another way, let each number equal x. The first five nonzero multiples of x are 1x, 2x, 3x, 4x and 5x.
The first 10 multiples of 3 are: 3, 6, 9, 12, 15, 18, 21, 24, 27, and 30.
That's an infinite list.
First 12 multiples of 9: 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, 108.
The first six multiples of 3 are 3, 6, 9, 12, 15, and 18. They are the products of 3 and the nonzero integers 1, 2, 3, 4, 5, and 6.
The first three multiples of 3 are 3, 6, 9 The first three multiples of 9 are 9, 18, 27 As the lowest common multiples of 3 and 9 is 9, the common multiples of 3 and 9 are the multiples of 9, thus: The first three common multiples of 3 and 9 are 9, 18, 27
1,1.5,2,2.25,3,4,4.5,6,9there's 9.....because it's a perfect square, it's normal 5 pairs of multiples(to make your required 10), is reduced to 4 1/2. One of its multiples is used with itself to form 9(3). Since two different integers cannot be squared and still equal the same number, you cannot reach 10. 9 is as close as you can get.
9x1= 9 9x2= 18 9x3= 27 9x4= 36 9x5= 45 9x6= 54 Is this what you mean?
3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36
9, 18, 27, 36, 45, 54.
The first two multiples are 9 and 8.