Prime No: between 1000 to 9999= 54_( 42x3)
From 1000 to 9999 (inclusive) there are 9999 - 1000 + 1 = 9000 integers. Half of which are even, half of which are odd. So the answer is 9000/2 = 4,500.
That would be 10,000.
9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, 108 and just keep adding nine until you get to 9999
500 of them.
To find the number of 4-digit numbers that are multiples of 9, we first determine the range of 4-digit numbers, which is from 1000 to 9999. Next, we calculate the first and last multiples of 9 within this range, which are 1008 and 9999 respectively. To find the total number of multiples of 9 in this range, we divide the difference between the last and first multiples by 9 and add 1, resulting in (9999 - 1008) / 9 + 1 = 999. Therefore, there are 999 4-digit numbers that are multiples of 9.
Prime No: between 1000 to 9999= 54_( 42x3)
From 1000 to 9999 (inclusive) there are 9999 - 1000 + 1 = 9000 integers. Half of which are even, half of which are odd. So the answer is 9000/2 = 4,500.
There are 2828 integers between 1000 and 9999.
13 of them.
There are 10 palindromes divisible by 9 between 1000 and 9999.
from 1000 to 9999, ie 9999 - 999 = 9000
0.999
9,999, 19,998, 29,997, 39,996, 49,995
That would be 10,000.
68 of them.
1,000 multiplied by 9,999 is 9,999,000.