1001, 1014, 10027 and just keep adding 13 till you get to 9997.
Prime No: between 1000 to 9999= 54_( 42x3)
From 1000 to 9999 (inclusive) there are 9999 - 1000 + 1 = 9000 integers. Half of which are even, half of which are odd. So the answer is 9000/2 = 4,500.
That would be 10,000.
9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, 108 and just keep adding nine until you get to 9999
Multiples of 13 include 13, 26, 39 and so on. For them to be common, they need to be compared to another set of multiples.
Prime No: between 1000 to 9999= 54_( 42x3)
Oh, what a happy little question! To find how many 4-digit numbers are multiples of 9, we need to see how many multiples of 9 fall between 1000 and 9999. To do this, we divide the range's endpoints by 9 and subtract the whole numbers in between. By doing this gentle math, we can find the number of delightful 4-digit numbers that are multiples of 9.
From 1000 to 9999 (inclusive) there are 9999 - 1000 + 1 = 9000 integers. Half of which are even, half of which are odd. So the answer is 9000/2 = 4,500.
There are 2828 integers between 1000 and 9999.
13 of them.
There are 10 palindromes divisible by 9 between 1000 and 9999.
from 1000 to 9999, ie 9999 - 999 = 9000
0.999
To round off 9999 to the nearest 1000, you look at the hundreds place, which is 9 in this case. Since 9 is greater than or equal to 5, you round up. Therefore, 9999 rounded to the nearest 1000 is 10000.
9,999, 19,998, 29,997, 39,996, 49,995
68 of them.
That would be 10,000.