1001, 1014, 10027 and just keep adding 13 till you get to 9997.
Prime No: between 1000 to 9999= 54_( 42x3)
From 1000 to 9999 (inclusive) there are 9999 - 1000 + 1 = 9000 integers. Half of which are even, half of which are odd. So the answer is 9000/2 = 4,500.
That would be 10,000.
9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, 108 and just keep adding nine until you get to 9999
Multiples of 13 include 13, 26, 39 and so on. For them to be common, they need to be compared to another set of multiples.
Prime No: between 1000 to 9999= 54_( 42x3)
From 1000 to 9999 (inclusive) there are 9999 - 1000 + 1 = 9000 integers. Half of which are even, half of which are odd. So the answer is 9000/2 = 4,500.
There are 2828 integers between 1000 and 9999.
Well, honey, to find the number of 4-digit multiples of 9, you just need to divide the largest 4-digit multiple of 9 (9999) by 9 and subtract the smallest 4-digit multiple of 9 (1008) divided by 9. So, 9999 ÷ 9 - 1008 ÷ 9 = 1111 - 112 = 999. That's right, there are 999 4-digit numbers that are multiples of 9.
13 of them.
There are 10 palindromes divisible by 9 between 1000 and 9999.
from 1000 to 9999, ie 9999 - 999 = 9000
0.999
9,999, 19,998, 29,997, 39,996, 49,995
That would be 10,000.
68 of them.
1,000 multiplied by 9,999 is 9,999,000.