There are a few options for listing five prime numbers using the digits zero to nine only once:2, 3, 5, 7, 8649012, 5, 13, 647, 809
7x(2-1)=7 7x(5-3)=14 7x(9-6)=21 7x(8-4)=28 7x(7+0)=49 7, 14, 28, 56. 903
The multiples of 16 are numbers that can be divided by 16 without leaving a remainder. The multiples of 16 are 16, 32, 48, 64, 80, and so on. Similarly, the multiples of 18 are numbers that can be divided by 18 without leaving a remainder. The multiples of 18 are 18, 36, 54, 72, 90, and so on.
place the digits 1 through 9 into three 3-digit numbers of an addition problem only using 1 through 9 once each
To find the second common multiple of two numbers, you first need to identify the least common multiple (LCM) of the two numbers. The LCM is the smallest number that is a multiple of both numbers. Once you have the LCM, you can then find the second common multiple by adding the LCM to the LCM itself. This will give you the second common multiple of the two numbers.
Five multiples of three that use each digit from 0 to 9 only once are: 12, 30, 45, 69, and 87.
21 and three left over
7, 28, 49, 63, 105 is the series of multiples of 7 using 0-9 only once.
Any number using each of the digits once will be a multiple of 3: eg 1597864302
six
4*3*2 = 24 of them.
There are four of them: 739, 793, 937, and 973 .
7, 42, 63, 98, 105
There are 5*4*3 = 60 such numbers.
6 - 123, 132, 213, 231, 312, and 321.
234, 243, 324, 342, 423, and 432.
-8