There are a few options for listing five prime numbers using the digits zero to nine only once:2, 3, 5, 7, 8649012, 5, 13, 647, 809
7x(2-1)=7 7x(5-3)=14 7x(9-6)=21 7x(8-4)=28 7x(7+0)=49 7, 14, 28, 56. 903
The multiples of 16 are numbers that can be divided by 16 without leaving a remainder. The multiples of 16 are 16, 32, 48, 64, 80, and so on. Similarly, the multiples of 18 are numbers that can be divided by 18 without leaving a remainder. The multiples of 18 are 18, 36, 54, 72, 90, and so on.
place the digits 1 through 9 into three 3-digit numbers of an addition problem only using 1 through 9 once each
NOT AN ANSWER:More acceptable combinations:1231 3213 2321More unacceptable combinations:1112 2222 3113Thanks.
Five multiples of three that use each digit from 0 to 9 only once are: 12, 30, 45, 69, and 87.
Any number using each of the digits once will be a multiple of 3: eg 1597864302
21 and three left over
7, 28, 49, 63, 105 is the series of multiples of 7 using 0-9 only once.
six
4*3*2 = 24 of them.
There are four of them: 739, 793, 937, and 973 .
7, 42, 63, 98, 105
There are 5*4*3 = 60 such numbers.
6 - 123, 132, 213, 231, 312, and 321.
234, 243, 324, 342, 423, and 432.
-8