Well, honey, if we're following the pattern of subtracting 2, then 4, then 8, the next three numbers would be 109, 97, and 73. But hey, who am I to tell you what to do? You do you, boo.
25, 49 and 121
Numbers having exactly three factors are the squares of prime numbers. Examples of these numbers greater than 100 are 121, 169, 289, 361, 529, 841, etc.
11 x 11 = 121
11 x 11 = 121
1, 11, and 121. (This number has an odd number of factors because it is a perfect square: 11 * 11 = 121.)
21 The pattern is 121, 12321, 1234321
The first thing to notice is that all the numbers in the sequence are square numbers. 25=5x5 36=6x6 49=7x7 64=8x8 81=9x9 So the next three numbers to be squared are 10, 11 and 12. 10x10=100 11x11=121 12x12=144 Thus, the next three numbers in the sequence are 100, 121, 144 The equation for the sequence is (n+4)2
25 36 49 64 81 100 121 144
The numbers are 120, 121 and 122.
There appears to be no discernible pattern for these numbers, other than them increasing in arbitrary multiples of 6.
112 = 121 and 122 = 144.
121, 169, 289
364
To find the HCF of 3 numbers you first need to write them as the product of their prime factors. In this case you get: 11 = 11 33 = 3x11 121 = 11x11 The next step is to identify any common prime factors. In this case, all three numbers have an 11 as a prime factor. Therefore, the HCF of 11, 33 and 121 is 11.
25, 49 and 121
111
121, 125 and 128.