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If you consider row 0 as the row consisting of the single 1, then row 100 has 6 odd numbers.
The sum of the numbers in the nth row of Pascal's triangle is equal to 2^n. Therefore, the sum of the numbers in the 100th row of Pascal's triangle would be 2^100. This formula is derived from the properties of Pascal's triangle, where each number is a combination of the two numbers above it.
8,000. each row's sum is the row # cubed. so the 20th row is 20*20*20 = 8000
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