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Q: What are the prime numbers divisible by 3?

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There is only one prime number divisible by 3 and it is 3 itself which is a prime number.

There aren't any prime numbers divisible by 4. Prime numbers aren't divisible by anything except 1 and the number.

The first three prime numbers are 2,3,5. The smallest number divisible by 2,3 and 5 is 30 (2*3*5).

2 * 3 * 5 * 7 = 210 is the smallest one divisible by four unique prime numbers. However, there are an infinite number of them, since there are an infinite number of primes.

24 is a composite number.24 is NOT a prime number.

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No prime numbers are divisible by 3. By definition a prime number isn't divisible by anything but itself and 1.

rectify the question first.. if it is prime then how it is possible to divisible by 3 Prime numbers that are divisible by 3 don't exist. It's a contradictio in terminis ;)

75 is not a prime number as it is divisible by 3 and 5. Prime numbers are numbers that are only divisible by 1 and themselves.

Prime numbers are divisible because any numbers that are divisible are prime. If a number isn't divisible, it isn't prime. Prime numbers have to be divisible by at least one pair of numbers to be prime.

Prime numbers are only divisible by 1 and itself... so no prime number can be divisible by the numbers you listed.

There are no prime numbers divisible by 435. 435 is divisible by 3, 5 and 29

57 is divisible by the prime numbers of 3 and 19

There is only one prime number divisible by 3 and it is 3 itself which is a prime number.

No prime numbers can be equal to 33, as 33 is not a prime number. It is divisible by 3. Prime numbers are only divisible by 1 and themselves, and 33 does not meet this criterion.

No. For example, 9 wouldn't be prime because it is divisible by 3.

Yes. The prime factorization of 75 is 3 x 5 x 5. So 75 is divisible by the two prime numbers 3 and 5.

3663 is divisible by 3 and 9. Prime numbers are only divisible by 1 and themselves.