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Q: What is the smallest number divisible by the first three prime numbers?

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The smallest number divisible by first four prime numbers is 2x3x5x7 = 210.

It is 2520.

2520

the answer is 120 because the first three prime numbers are 2,3,5 and the first three composite numbers are 4,6,8.

Just multiply the first five prime numbers! 2x3x5x7x11 = 6x35x11 = 210x11 = 2310. Any multiple of this number "has the first five prime numbers as factors", but 2310 is the smallest such number.

Related questions

The smallest number divisible by first four prime numbers is 2x3x5x7 = 210.

11

2310

It is 2520.

2520

The smallest three-digit number divisible by the first three prime numbers (2, 3, and 5) and the first three composite numbers (4, 6, and 8) is 120.

The smallest number evenly divisible by the numbers 1-12 is 60. 60 is also be by 0, but not by 13.

120

the answer is 120 because the first three prime numbers are 2,3,5 and the first three composite numbers are 4,6,8.

2520

The numbers that are divisible by two are infinite. The first four are: 2,4,6,8 . . .

The list of numbers that are divisible by 11 is infinite. The first four are: 11,22,33,44 . . .

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