7x(2-1)=7 7x(5-3)=14 7x(9-6)=21 7x(8-4)=28 7x(7+0)=49
7, 14, 28, 56. 903
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That's not going to work. Multiples of 5 end in 5 or 0. With three numbers, one of those would have to repeat.
There are a few options for listing five prime numbers using the digits zero to nine only once:2, 3, 5, 7, 8649012, 5, 13, 647, 809
The multiples of 16 are numbers that can be divided by 16 without leaving a remainder. The multiples of 16 are 16, 32, 48, 64, 80, and so on. Similarly, the multiples of 18 are numbers that can be divided by 18 without leaving a remainder. The multiples of 18 are 18, 36, 54, 72, 90, and so on.
To find the second common multiple of two numbers, you first need to identify the least common multiple (LCM) of the two numbers. The LCM is the smallest number that is a multiple of both numbers. Once you have the LCM, you can then find the second common multiple by adding the LCM to the LCM itself. This will give you the second common multiple of the two numbers.
place the digits 1 through 9 into three 3-digit numbers of an addition problem only using 1 through 9 once each