The question refers to two factors of 132 that are consecutive integers.
The answer is 11 & 12, as 11 x 12 = 132
This can be solved as follows.
Let n be the smaller of the two numbers then (n + 1) is the other number.
n(n + 1) = 132
n2 + n = 132
n2 + n - 132 = 0............which can be factored as (n + 12 )(n - 11) = 0
As we are only concerned with the positive integer result then this occurs when n - 11 = 0, that is when n = 11, thus (n + 1) = 12.
NOTE : Integers can also be negative and this applies to the other solution when n + 12 = 0, so n = -12 and consequently (n + 1) = -11 giving the result that -12 x -11 = 132.
The numbers are 65 and 67.
There are two consecutive even integers. The numbers are 118 and 120.
There are no two consecutive integers, negative or positive, whose product is 440.
There are no two consecutive integers whose product is 421 - the product of 20 and 21 is 420.
Divide the sum of the two consecutive odd integers by 2: 156/2=78. The two consecutive odd integers will be one more and one less than 78, so the smaller will be 77 and the larger will be 79.
The product of two consecutive integers is 132. Find the two integers. They are: 11*12 = 132
The numbers are 65 and 67.
Divide the sum of the three consecutive odd integers by 3: 402/3 = 134. The smallest of these integers will be two less than 134 and the largest will be two more than 134, so the three consecutive odd integers will be 132, 134, and 136.
43, 44, 45
There are no "two consecutive integers" that can do that.But there are two consecutive even integers that can: 8 and 10 .
132/3 = 44 43, 44, 45
The two consecutive integers are 19 and 20.
3 consecutive even integers whose sum is 396 are 130, 132 and 134.
The two consecutive, even integers are 350 and 352.
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
"Consecutive" integers are integers that have no other integer between them.
There are two consecutive odd integers. The numbers are 39 and 41.