answersLogoWhite

0

The question refers to two factors of 132 that are consecutive integers.

The answer is 11 & 12, as 11 x 12 = 132

This can be solved as follows.

Let n be the smaller of the two numbers then (n + 1) is the other number.

n(n + 1) = 132

n2 + n = 132

n2 + n - 132 = 0............which can be factored as (n + 12 )(n - 11) = 0

As we are only concerned with the positive integer result then this occurs when n - 11 = 0, that is when n = 11, thus (n + 1) = 12.

NOTE : Integers can also be negative and this applies to the other solution when n + 12 = 0, so n = -12 and consequently (n + 1) = -11 giving the result that -12 x -11 = 132.

User Avatar

Wiki User

13y ago

Still curious? Ask our experts.

Chat with our AI personalities

BlakeBlake
As your older brother, I've been where you are—maybe not exactly, but close enough.
Chat with Blake
ProfessorProfessor
I will give you the most educated answer.
Chat with Professor
RafaRafa
There's no fun in playing it safe. Why not try something a little unhinged?
Chat with Rafa

Add your answer:

Earn +20 pts
Q: What are two consecutive integers of 132?
Write your answer...
Submit
Still have questions?
magnify glass
imp