504/3 = 168 so the three numbers are 167, 168 and 169.504/3 = 168 so the three numbers are 167, 168 and 169.504/3 = 168 so the three numbers are 167, 168 and 169.504/3 = 168 so the three numbers are 167, 168 and 169.
As a product of its prime factors: 2*2*2*3*7 = 168
2 x 2 x 2 x 3 x 7 = 168
As a product of its prime factors in exponents: 22*33 = 108 As a product of its prime factors in exponents: 23*29 = 232 As a product of its prime factors in exponents: 23*3*7 = 168
12 x 14 = 168
Call the smaller of the two consecutive integers n. Then, from the problem statement: n(n+2) = 168, or n2 + 2n - 168 = 0, or (n + 14)(n - 12) = 0, which is true when n = -14 or +12. Therefore, the two integers sought are 12 and 14.
168 and 169
The numbers are 167, 168 and 169.
168.
The smallest is 55.
55
It is a list of three even integers.
The product is: 168
The smallest is 55.
55 + 56 + 57.
168/3 = 56 so 54, 56 and 58
55