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Yeah, those two integers don't exist

12 x 13 is 156 - too low

the very next integers or too high

13 x 14 is 182 - too high

if it helps 12 x 14 is 168, but these are not consecutive

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Q: What are two consecutive integers whose product is 168?

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504/3 = 168 so the three numbers are 167, 168 and 169.504/3 = 168 so the three numbers are 167, 168 and 169.504/3 = 168 so the three numbers are 167, 168 and 169.504/3 = 168 so the three numbers are 167, 168 and 169.

As a product of its prime factors: 2*2*2*3*7 = 168

2 x 2 x 2 x 3 x 7 = 168

As a product of its prime factors in exponents: 22*33 = 108 As a product of its prime factors in exponents: 23*29 = 232 As a product of its prime factors in exponents: 23*3*7 = 168

12 x 14 = 168

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Call the smaller of the two consecutive integers n. Then, from the problem statement: n(n+2) = 168, or n2 + 2n - 168 = 0, or (n + 14)(n - 12) = 0, which is true when n = -14 or +12. Therefore, the two integers sought are 12 and 14.

168 and 169

The numbers are 167, 168 and 169.

168.

The smallest is 55.

55

It is a list of three even integers.

The product is: 168

The smallest is 55.

55 + 56 + 57.

168/3 = 56 so 54, 56 and 58

55