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Find the integers if the product of two consecutive even integers is 168?
Wiki User
∙ 13y ago
Call the smaller of the two consecutive integers n. Then, from the problem statement:
n(n+2) = 168, or n2 + 2n - 168 = 0, or (n + 14)(n - 12) = 0, which is true when n = -14 or +12. Therefore, the two integers sought are 12 and 14.
Wiki User
∙ 13y ago
Anonymous
n(n+2)=168
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