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Call the smaller of the two consecutive integers n. Then, from the problem statement:

n(n+2) = 168, or n2 + 2n - 168 = 0, or (n + 14)(n - 12) = 0, which is true when n = -14 or +12. Therefore, the two integers sought are 12 and 14.

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n(n+2)=168

Q: Find the integers if the product of two consecutive even integers is 168?

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I think you mean consecutive even integers: 20 & 22

The sum of the squares of two consecutive positive even integers is 340. Find the integers.

There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.

26 and 28

The even integers are 22, 24 and 26.

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10 and 12

I think you mean consecutive even integers: 20 & 22

8

The product of 2 consecutive positive number is 48. Find the 2 numbers

The sum of the squares of two consecutive positive even integers is 340. Find the integers.

They are 6, 8, 10 and 12.

There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.

No. There is no set of three consecutive even integers with a sum of 40.

The numbers are 82, 84, 86 and 88.

4,6,8,10

26 and 28

The numbers are 6 and 8.