Let the consecutive multiples of 7 be 7x and 7(x+1).
7x + 7(x+1) = 126
7x + 7x + 7 = 126
14x + 7 + 126
14x = 126 - 7
14x = 119
x = 119/14
x = 8.5
For 7x to be a multiple of 7, x must be a whole number, so there are no such consecutive multiples.
They are 63 and 126
It is -7,-6,-5,-4!
88 / 4 = 22 = 4 + 5 + 6 + 7... so 4(4) + 4(5) + 4(6) + 4(7) = 16 + 20 + 24 + 28 = 88
The lowest common multiple of 7 and 9 is 63. The common multiples of 7 and 9 are therefore the infinite set of multiples of 63. Thus, the common multiples of 7 and 9 are 63, 126, 189, 252, 315, 378, 441, 504, 567, 630, 693, and so on.
17 is the only prime number that is the sum of four consecutive prime numbers. 2 + 3 + 5 + 7 = 17
91
All odd numbers are the sum of two consecutive numbers. Odd multiples of 7 less than 25 are 7 and 21.
18 times 7 = 126
7 x 18 = 126 126 is a common multiple of 7 and 18
They are: 2*3*3*7 = 126
91, 98, 105, 112
Any multiple of 126.
Consecutive numbers can't both be multiples of 7. The LCM of consecutive numbers is their product. 14 and 15 are consecutive numbers whose LCM is a multiple of 7 that is greater than 200.
63, 126, 189 and so on.
42, 84, 126
They are 63 and 126
42, 84, 126 and so on.