Let the consecutive multiples of 7 be 7x and 7(x+1).
7x + 7(x+1) = 126
7x + 7x + 7 = 126
14x + 7 + 126
14x = 126 - 7
14x = 119
x = 119/14
x = 8.5
For 7x to be a multiple of 7, x must be a whole number, so there are no such consecutive multiples.
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They are 63 and 126
It is -7,-6,-5,-4!
88 / 4 = 22 = 4 + 5 + 6 + 7... so 4(4) + 4(5) + 4(6) + 4(7) = 16 + 20 + 24 + 28 = 88
The lowest common multiple of 7 and 9 is 63. The common multiples of 7 and 9 are therefore the infinite set of multiples of 63. Thus, the common multiples of 7 and 9 are 63, 126, 189, 252, 315, 378, 441, 504, 567, 630, 693, and so on.
17 is the only prime number that is the sum of four consecutive prime numbers. 2 + 3 + 5 + 7 = 17