1, 2, 4, 8, 16, 32.
Each of these numbers will go evenly into 80: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80.
These whole numbers go evenly into 64: 1, 2, 4, 8, 16, 32, 64.
The largest number that will divide evenly into 64 with no remainder is 64.
20% of 80 is 16 and 80-16= 64
The HCF of 16 and 64 is 16
no but 2 goes evenly into 62 and 80 just do 31x2=62 and 40x=80
27 is 3 to the 3rd power, and 64 is 2 to the 6th power, so the only number that goes into both evenly is one (1).
1, 2, 4, 8, 16, 32, 64
Yes, it goes in 16 times (16x4=64)
1, 2, 4, 8, 16, 32, 64.
The only common factor of 49 and 64 (whole number that goes into both of them evenly) is ' 1 '.
1, 2, 4, 8, 16, 32.
No because it will have a remainder of 12
Each of these numbers will go evenly into 80: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80.
2 2 goes into any even number right away evenly. In this case though, the highest number would be 4.
Sixteen is a divisor of 64 because it goes evenly into 64. Here are all of 64's divisors: 1, 2, 4, 8, 16, 32, 64.