Yes, it goes in 16 times (16x4=64)
64/4 = 16 with no remainder. The answer is yes, it does.
1, 2, 4.
1, 2, 4 and 8 will go into both numbers evenly with no remainders
No. 64 is not evenly divisible by six.
1, 2, 4, 8, 16, 32, 64.
64/4 = 16 with no remainder. The answer is yes, it does.
These whole numbers go evenly into 64: 1, 2, 4, 8, 16, 32, 64.
Not evenly because there will be a remainder of 4
1, 2, 4.
2, 4, and 8 will evenly divide into both.
Not evenly.
1, 2, 4 and 8 will go into both numbers evenly with no remainders
No. 64 is not evenly divisible by six.
1, 2, 4, 8, 16, 32, 64, 128, 256.
1, 2, 4, 7, 8, 16, 32, 64, and of course 128 ;)
No. These are the numbers that divide evenly into 64: 1 2 4 8 16 32 and 64.
It is just 1