Yes, it goes in 16 times (16x4=64)
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64/4 = 16 with no remainder. The answer is yes, it does.
1, 2, 4.
1, 2, 4 and 8 will go into both numbers evenly with no remainders
No. 64 is not evenly divisible by six.
1, 2, 4, 8, 16, 32, 64.