These are the factors of 393 (the whole numbers that go into 393 evenly): 1, 3, 131, 393.1 x 393, 3 x 131, 131 x 3, 393 x 1
Just get them all to a common base - 4 twelfths + 6 twelfths = 10 twelfths OR 5/6
The factors of 2620 are 1, 2, 4, 5, 10, 20, 131, 262, 524, 655, 1310, and 2620. The prime factors are 2, 2, 5, and 131.
All those ending with 0, 2, 4, 6 or 8
to multiply 2 digit numbers together you would firstly set out a solider sum like this 34 x 47 then you would do the 7 column like normal 34 47 221 then for the 4 column you would add a magic 0 to the end like then add up 221 and 1360 and u would get 1581 34 47 221 1360 1581
Math is done the same, line it up and add. Except you must carry the 4 instead of the 10. So the first column is easy 1 + 1 is 2. Next 2+3 = 5. Being base 4 though you cant have a five so you carry the 4 (add 1 to the next column) and you leave the extra 1 in the 4's place. Next you have 2+1+1=4 in the third column. Once again you carry the 4 as a 1 to the next column, and have 0 left over. Lastly you have the carried 1.This means the answer is 1012.You can check with decimal. 221= 41 (2*16+2*4+1*1) and 131= 29 (1*16+3*4+1*1).41+79=70Convert to base four and you get 1012! (1*64+0*16+1*4+2*1=70)
1 + 4 + 16 + 25 + 36 + 49 = 131
32 base 4
131
5 + (16 x 8) - (8/4) = 131
Double Play, Shortstop to Second Base to 1st base.
Base = x + 4 Altitude = 4*base = 4*(x+4) Area = 0.5*base*altitude = 0.5*(x+4)*4*(x+4) = 2*(x+4)2
Depends on the pyramid. Most have 4 surfaces (3 faces plus a base) The Mayan pyramids had 5 surfaces (4 faces plus a base).
121 in base 4 = 16 + 8 + 1 (base ten) = 2584 in base 16 = 128 + 4 (base ten) = 132132 + 25 = 157(base 10) = 9D (base 16) = 2131 (base 4)
131 grams = 4 ounces
√131 = ±11.4455 (to 4 decimal places)
The first ten positive integer multiples of 221 are: 1 x 221 = 221 2 x 221 = 442 3 x 221 = 663 4 x 221 = 884 5 x 221 = 1105 6 x 221 = 1326 7 x 221 = 1547 8 x 221 = 1768 9 x 221 = 1989 10 x 221 = 2210