It is already expressed as a whole number in the form of 3150
It is: 3150/3600 = 7/8 in its lowest terms
As a product of its prime factors: 2*3*3*5*5*7 = 3150 or as 2*32*52*7 = 3150
The idea is to subtract 10p minus 4p.
The one that is not a 10p is a 20p. The other coin is a 10p. The question/riddle does not say that neither coin is a 10p, only that one of them is not.
3150
3150
It is already expressed as a whole number in the form of 3150
3150
3200
3150 to a percent = 315000% to put 3150 to a percent, multiply 3150 by 100%: Example: 3150 * 100% = 315000%
1, 2, 3, 5, 6, 7, 9, 10 5 x 630 = 3150 10 x 315 = 3150 6 x 525 = 3150 2 x 1575= 3150 1 x 3150 = 3150 7 x 450 = 3150 9 x 350 = 3150 3 x 1050 = 3150
15% of 3,150 = 15% * 3150 = 0.15 * 3150 = 472.5
the product of 10p (p–q) is 10p²-10pq Given: 10p (p–q) To find : the product of 10p (p–q) Solution: we have to find the product of 10p (p–q). so product of any number means the multiplication multiply (p–q). by 10p we get, =10p× (p–q) =10p×p-10p× q =10p²-10pq the product of 10p (p–q) is 10p²-10pq
Answer: 3150 m = 10334.645 '
7p-10p = -3
30p = 20p + 5p + 5p 40p = 20p + 10p + 10p