How many numbers are 10 unitβs from 0 on the number line
The distance the number is from zero. For example, + 19 is 19 units of length on the positive side of the number line , to the right of the zero position. - 19 is 19 units of length going the other way, to the left of the zero position on a number line.
2
12, -12
The nth triangular number is given by ½ × n × (n+1)→ the 5857th triangular number is ½ × 5857 × 5858 = 17,155,153, so its units digit is a 3.------------------------------------------------------------Alternatively,If you look at the units digits of the first 20 triangular numbers they are {1, 3, 6, 0, 5, 1, 8, 6, 5, 5, 6, 8, 1, 5, 0, 6, 3, 1, 0, 0}At this stage, as we are only concerned with the units digit, as we now have a 0 for the units digit, when 21 is added it is the same as adding 1 to 0 to give a 1, for the 22nd triangular number, we are adding 2 to the 1 to give 3, and so on - the sequence of 20 digits is repeating.To find the units digit of the nth triangular number, find the remainder of n divided by 20 and its units digit will be that digit in the sequence (if the remainder is 0, use the 20th number). To find the remainder when divided by 20 is very simple by looking at only the tens digit and the units digit:If the tens digit is even (ie one of {0, 2, 4, 6, 8}), the remainder is the units digitIf the tens digit is odd (ie one of {1, 3, 5, 7, 9}), the remainder is the units digit + 10.5857 ÷ 20 = ... remainder 17; the 17th digit of the above sequence is a 3, so the units digit of the 5857th triangular number is a 3.This trick can be used for much larger triangular numbers which calculators cannot calculate exactly using the above formula. eg the units digit of the 1234567890123456789th triangular number is... 1234567890123456789 ÷ 20 = .... remainder 9, so this triangular number's units digit is the 9th digit of the above sequence which is a 5.
-4
It is 4 units.
-3
10 units ------------------------------------------------ 4 - -6 = 4 + 6 = 10 On a number line: You need to go 6 units from -6 to 0, and then another 4 units from 0 to 4 making 6 + 4 = 10 units in total.
-31
the number 2 is two units to the right of 0 on the number line. the number -2 is two units to the left of 0
If you start at 0 then: 0+5-3+4=6 I hope it helped you
(-4,-2)
Which transformations could have been used to move the platter to the new location? A. a translation 9 units left and a translation 3 units down B. a reflection across MN and a translation 4 units left C. a reflection across MN and a translation 8 units left D. a rotation 180Β° clockwise about N and a translation 4 units left
The base of the right-angled triangle = 4 units The height = 6 units The area = 0.5 * base * height = 12 square units =========================
Vertices or points: (0, 0) (3, 4) and (6,0) Type of shape: an isosceles triangle Base: 6 units Height: 4 units Area: 0.5*6*4 = 12 square units
The two points are (2, -3) and (-4, 5). To start at the origin, O, which is (0, 0). Then, to find any point, such as (p, q), you move p units to the right (to the left if p is negative) and then q units up (down if q is negative). So, the first point is 2 units to the righ and 3 down. The second is 4 to the left and 5 up.