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Yes, 120 is divisible by 3. A good rule of thumb for the multiples of 3 is to add up the digits in the number. If the number that comes out is divisible by 3, then it is a multiple of 3. For example, in 120, 1 + 2 + 0 = 3. Therefore, the number is divisible by 3. The process can be repeated for larger numbers. For example, 2688 is divisible by 3 because 2 + 6 + 8 + 8 = 24, and 2 + 4 = 6.
You could be 121.
To find a number between 120 and 130 that is divisible by 3 and has a digit sum divisible by 4, we first consider the numbers in that range: 121, 122, 123, 124, 125, 126, 127, 128, 129. Next, we calculate the digit sum of each number: 121 (1+2+1=4), 122 (1+2+2=5), 123 (1+2+3=6), 124 (1+2+4=7), 125 (1+2+5=8), 126 (1+2+6=9), 127 (1+2+7=10), 128 (1+2+8=11), 129 (1+2+9=12). Therefore, the number between 120 and 130 that is divisible by 3 and has a digit sum divisible by 4 is 123.
Well, honey, if you want a number that's divisible by 2, 3, 5, 6, and 10, you're looking for the smallest common multiple of those numbers. The smallest 3-digit number that fits the bill is 120, because it's divisible by all those numbers. So, there you go, darling, hope that helps!
It is: 840