129.129.129.129.
Yes, 120 is divisible by 3. A good rule of thumb for the multiples of 3 is to add up the digits in the number. If the number that comes out is divisible by 3, then it is a multiple of 3. For example, in 120, 1 + 2 + 0 = 3. Therefore, the number is divisible by 3. The process can be repeated for larger numbers. For example, 2688 is divisible by 3 because 2 + 6 + 8 + 8 = 24, and 2 + 4 = 6.
You could be 121.
Quite a few. 120, 150, 180 and so on.
It is: 840
120
No, 120 is not the smallest number that is divisible by 1,2,3,4,5 and 6.
40 and 3 have a difference of 37 and when multiplied equal 120.
The sum of its digits is 1+2+0 = 3 which is divisible by 3. So 120 is divisible by 3. The number 120 ends in a 0 and so it is divisible by 5.
3*8*5=120, therefore 120 is divisible by 3, 8 and 5.
120
120 is one such number.
No.First off, 120 is not divisible by 9. (The sum of the digits of 120 is "3"; a number is divisible by nine if and only if the sum of its digits is divisible by nine.) For that matter, it's not divisible by 36 either; since 36 is itself divisible by 9, any number which is not divisible by 9 cannot be divisible by 36.The smallest number that's divisible by 1, 2, 3, 6, 9, 12 and 36 is "36" (it's also divisible by 4, which you left out).
If you have a few different numbers that you are using, divide them each by 8 and if you get a whole number, that number is divisible. If you are trying to figure out what is divisible by 8, you can use a divisibility test.A number is divisible by 8 if:the number formed by the last three digits is divisible by 8.So, an example of this would be:7, 120.This number is divisible by 8 because 120 (the last 3 digits) is divisible by 8!
Assuming no repeated digits, lowest first, 20; in any order 120; Allowing repeated digits: 216
Any number ending in 0 is always divisible by 5 and 2 (and more).
The lowest common multiple is the smallest multiple that is exactly divisible by every member of a set of numbers. The LCM of 8, 12 and 20 is 120.