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(2/3)x - 6 has a rational coefficient.

(sq root 2)x + 4 has an irrational coefficient.

Q: What is a factor that is not the product of polynomials having integer coefficients?

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(x^2 + 1)(x^2 - 4x + 13)

This is a clever question. I would say: "Always". To be more precise: The product is never greater than either factor, and if neither factor is ' 1 ', then the product is always less than both.

There is no specific term for such polynomials. They may be referred to as are polynomials with only purely complex roots.

The fundamental theorem of arithmetic says any integer can be factored into a unique product of primes. The is the prime factored form.

Every number except zero is a factor of every other number. Usually this kind of question is intended as a question about integral factors, those that can be paired with another integer to produce the number as a product. In that sense, 9 is not an integral factor of 11, because the paired number with 9 is 11/9, a number that is not an integer.

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In that case, it may, or may not, be possible to factor it using non-integer coefficients.

(x^2 + 1)(x^2 - 4x + 13)

That is correct.

This is a clever question. I would say: "Always". To be more precise: The product is never greater than either factor, and if neither factor is ' 1 ', then the product is always less than both.

They will certainly share the factor 1. Other than that, the probability is 1: it is nearly a certainty that that they will not share another common factor..

The product of an odd and even number will always have 2 as a factor. Therefore, it will always be even.

9

You write it as x2 + 6x - 5 = 0, and then do one of the following: 1) Factor the polynomial. Note that the product of two number is zero if one of the factors is zero. 2) Complete the square. 3) The most general method to use - for polynomials that are difficult to factor - is the quadratic formula. In this case, the coefficients are a = 1, b = 6, c = -5.

If a polynomial function, written in descending order, has integer coefficients, then any rational zero must be of the form ± p/q, where p is a factor of the constant term and q is a factor of the leading coefficient.

Do you care weather a random stranger on their computer cares how to factor polynomials. P.S. i do in fact care how to factor polynomials, but i'm most likely in the minority on this one.

Whenever there are polynomials of the form aX2+bX+c=0 then this type of equation is know as a quadratic equation. to solve these we usually break b into two parts such that there product is equal to a*c and I hope you know how to factor polynomials.

Multiply the first and last coefficients.2*3=6What two factors give you six but when combined give you -5-2 and -3Therefore2x-3)(x-1) will be the factored model.