There are many such pairs.
2+3
1+4
0+5
-1+6
-2+7
etc.
224, 225
-4 and -1
THere are two pair of consecutive integers. 52 = 25 < 30 < 36 = 62 So, one pair is 5 and 6 and the other pair is -6 and -5.
The sum will be negative also. (-3)+(-2)= m-5
1,2,9,14,5,6,13,4,3,10,7,12,11,8,15
3 and 5.
You cannot. The sum of negative integers will be negative.
12 x -7 = -84 12 + (-7) = 5
For a pair of integers (a) and (b), if their sum (a + b) is smaller than one of the integers (let's say (a)), it implies that (b) must be negative. Specifically, if (a + b < a), then (b) must be less than 0. For example, if (a = 5) and (b = -3), their sum (5 - 3 = 2), which is smaller than (5) but greater than (-3).
224, 225
Take any negative integers, say -5 and -10, their sum is -15 which is smaller than both of them. We could have used 0 as well, so I should have said any non-positive integers. To see that is does not work with positive integers, take 5 and 10 whose sum is 15 which is BIGGER than either one.
The answer is -5.
The pair of consecutive integers which add up to 55 are 27 and 28. Therefore, any consecutive pair of numbers below 27 and 28 add up to a total less than 55.
There is no pair of consecutive even integers whose sum is 264 - as their average is divisible by 4, that must mean that the sum of the unit digits of each of the pair of numbers could never be a multiple of 4 - which 264 is.
12 and -2
They will be the same absolute value with opposite signs. They don't even have to be integers.
-4 and -5