No because the discriminant is less than zero.
The Greatest Common Factor (GCF) of 64 and 128 is: 64
64 is not a factor of 8.Factor of a number x is always less than or equal to x.
The factor pairs of 64 are (64,1), (32,2), (16,4), and (8,8)
2,2,2,2,2,2 4,2,2,2,2 8,2,2,2 16,2,2 32,2 64
No because the discriminant is less than zero.
64 plus 64 plus 64 is 192.
33 = 2726 = 647 x 13 = 91
(8 + 3v)(8 + 3v) or (8 + 3v)2
3x3 + 192 3(x3 + 64) ========
(4x + 7)(16x2 - 28x + 49)
64 is the cube of 4 so: x3 + 64 = (x + 4)(x2 - 4x + 16)
It can be. 64 is a factor of 128, among others.
It means 64 plus 15It means 64 plus 15It means 64 plus 15It means 64 plus 15
-16x2 + x + 8 = -1/64(32x - 1 - √513)(32x - 1 + √513)
No, 3 is not a factor of 64.
No, 4 is a factor of 64.