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(x + 4)(x^2 - 4x + 16)

Q: Factor x3 plus 64

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x3 + 4x2 - 16x - 64 = (x + 4)(x + 4)(x - 4).

(x - 8)(x2 + 8x + 64)

x3+27y3 = (x+3y) · (x2-3xy+9y2)

x3 + 12x2 + 48x + 64= (x + 4)(x2 + 8x + 16)= (x + 4)(x + 4)(x + 4)= (x + 4)3

Subtract 1 from each side: x3 = 64; You might know that 4 cubed is 64, but if you don't then take log 64, divide it by 3 and take the antilog of your answer...

Related questions

3x3 + 192 3(x3 + 64) ========

x3 + 4x2 - 16x - 64 = (x + 4)(x + 4)(x - 4).

(x - 8)(x2 + 8x + 64)

x3 + 4x2 + x + 4 = (x + 4)(x2 + 1)

x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)

(x - 4)(x^2 + 4x + 16)

x3+27y3 = (x+3y) · (x2-3xy+9y2)

x3 + 12x2 + 48x + 64= (x + 4)(x2 + 8x + 16)= (x + 4)(x + 4)(x + 4)= (x + 4)3

x3 + 4x2 + 16x + 64 =x2*(x + 4) + 16(x + 4) = (x + 4)*(x2 + 16) which has no further real factors.

Subtract 1 from each side: x3 = 64; You might know that 4 cubed is 64, but if you don't then take log 64, divide it by 3 and take the antilog of your answer...

x2(x3 + 1) is the best you can do there.

x(x^2 + 2)