They are:
1, 2, 3, 4 and 5.
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There are 720 of them. The three digit counting numbers are 100-999. All multiples of 5 have their last digit as 0 or 5. There are 9 possible numbers {1-9} for the first digit, There are 10 possible numbers {0-9} for each of the first digits, There are 8 possible numbers {1-4, 6-9} for each of the first two digits, Making 9 x 10 x 8 = 720 possible 3 digit counting numbers not multiples of 5.
0,1,2,3,4,10,11,12,13,14,20,21,22,23,24,30,31,32,33,34, 40,41,42,43,44,100,101,102,103,104,110,111,112,113,114,120,121 There are 37 numbers here (0 to 36), written in base 5, as I was not certain if you wanted to include "0" or not.
The sum of the first 100 counting numbers (1-100) is 5,001.
yes! just think of it this way: when someone tells you start counting, you "naturally" start with 1, 2, 3, 4, 5,...and so on. that's helps you remember the words natural numbers, because you "naturally" start counting at 1. it's the same with counting numbers. if someone told you to start counting, you would start with 1, 2, 3, 4, 5,...and so on. this helps you remember counting numbers, because you start "counting" with 1. get it??! =D
Which 10 counting numbers? There is an infinity of counting numbers.