5
It is: 27
hcf(18, 54, 81) = 9. Using prime factorization: 18 = 2 x 3^2 54 = 2 x 3^3 81 = 3^4 hcf = 3^2 = 9
To find the highest common factor (HCF) of 81, 243, and 1215, we first need to find the prime factorization of each number. The prime factorization of 81 is 3^4, 243 is 3^5, and 1215 is 3^5 * 5. To find the HCF, we look for the highest power of each prime factor that appears in all the numbers. In this case, the highest power of 3 that appears in all three numbers is 3^4, so the HCF of 81, 243, and 1215 is 81.
9
It is: 5
It is: 9
It is: 27
The HCF is 1.
hcf(18, 54, 81) = 9. Using prime factorization: 18 = 2 x 3^2 54 = 2 x 3^3 81 = 3^4 hcf = 3^2 = 9
The GCF is 1.
The GCF is 27.
The GCF is 15.
HCF(26, 45) = 1. The numbers are co-prime.
To find the highest common factor (HCF) of 81, 243, and 1215, we first need to find the prime factorization of each number. The prime factorization of 81 is 3^4, 243 is 3^5, and 1215 is 3^5 * 5. To find the HCF, we look for the highest power of each prime factor that appears in all the numbers. In this case, the highest power of 3 that appears in all three numbers is 3^4, so the HCF of 81, 243, and 1215 is 81.
HCF is 3
The GCF is 1.
The GCF is 1.