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Prove that square root of 6 is irrational number?
If a/b=sqrt(6), then a2=6b2 On the other hand, given integers ''a'' and ''b'', because the valuation (i.e., highest power of 2 dividing a number) of 6b2 is odd, while the valuation of a2 is even, they must be distinct integers. Contradiction.
How do you tell a bra size?
The number is the measure (in inches) around your body (under the breasts). And the letter is the number of inches your breasts are from your chest. For example 1ins - A, 2ins - B, 3ins - C.
What is an example of an rational number?
A rational number is the set of number expressed in the form of a fraction a/b, where a and b are integers and b isn't equal to 0
Can you add an irrational number and a rational number?
Let `a` be a rational number and `b` be an irrational number,assume that the sum is rational. 1.a +b =c Where a and c are rational and b is irrational. 2.b=c-a Subtracting the same number a from each side. 3.b is irrational c-a is a rational number we arrived at a contradiction. So the sum is an irrational number.
In mathematics what is a rational number?
Any number that can be expressed as a ratio of two integers ( whole numbers) providing the second number is not zero. In symbols a number that can be put in the form a/b where a and b are integers ,and b does not equal zero
