The GCF of 9s and 63s^3 is 9s.
9.5 and 9.4999... (9s repeating).
There are 27 of them.
The two ways are 8.517 and 8.516999... (9s repeating).
There can be no answer to the question because it is based on a false assumption.0.3333... repeating = 1/3 : I don't see any 9s in the denominator!or 0.0111... repeating = 11/990 : I would not consider the last digit in the denominator to be 9.Having said that, the significance of 9 is that we count in blocks of one more: 10s.
The GCF of 9s and 63s^3 is 9s.
6b^2-13bs-63s^2 is factorised to (2b-9s)(3b+7s)
Since 9s is a factor of 36s, it is automatically the GCF.
4 x 9 = 36 36 + 1/3 = 361/3
You could have one No. 9 or a handful of No. 9s
9s + 7 = -11 9s = -18 s = -18/9 s = -2
Five 9s:(99 x 9 + 9) / 9 = 100
The equivalent is 7s+2s = 9s
You have to combine equal terms. -5r-9s+9r+3s-6 = -5r+9r-9s+3s-6 = 4r-6s-6
The next year after 1999 that will have three 9s in its title will be 2999.
5
Nine of them