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6b^2-13bs-63s^2 is factorised to (2b-9s)(3b+7s)

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Q: How do you factor the trinomial 6b2-13bs-63s2?

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That trinomial is unfactorable (the roots are not integers).

just like factoring any other trinomial.

That is the linear part.

(y10 + 2y5z3 + 4z6)

Change all the signs in the trinomial and then proceed as normal.

That's not a trinomial, but it factors to x(x + 19)

Take a trinomial. 2x2 - 3x - 2 Factor it. (2x + 1)(x - 2) Repeat as necessary.

You would factor out -1 (a) from a trinomial in an equation such as -a^2 +30a - 2a + 60 after the middle term has been separated. The final answer of this trinomial would then be (a-30) (a-30).

A factor of a perfect square trinomial is eithera number that is a factor of each term of the trinomial,a binomial that is a factor of the trinomial, ora product of the above two.For example, consider 4x2 + 8x + 4It has the factors2 or 4,(x + 1) or2x+2 = 2*(x+1) or 4x+4 = 4*(x+1)

It's not enough to copy the question off the test. If you don't tell us what the trinomial is, we can't factor it for you.

x + 8orx - 4

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