The GCF is 1.
GCF of 12 and 18 is 6
12 * n = 12n That is the best you can do without knowing what n is!
1, 2, 3, 4, 6, 12, n
12n > 36 n > 3
11n - 12n + 3 = 3 - n
The GCF is 1.
GCF of 12 and 18 is 6
Gather the m's and n's by rewriting it. 7m - 11n - n + 5m 7m + 5m -11n - n (7m + 5m) + (-11n - n) 12m - 12n ■
The net force is calculated by adding up all the forces acting on the object. In this case, the forces being applied to the left (11N and 12N) are greater than the force being applied to the right (3N). Therefore, the net force would be 11N + 12N - 3N = 20N to the left.
Assuming you mean 12m + 12n, you can use the distributive property to take out the common factor 12.
(m + 2n)(m - 6n)
6n(2n - 3)
The expression 12m + 12n is equal to 12 times the sum of m and n. This expression cannot be simplified further unless there are like terms that can be combined. If m and n are like terms, then the expression can be further simplified by factoring out the common factor of 12 to get 12(m + n).
Oh, dude, the greatest whole number that MUST be a factor of the sum of any six consecutive positive odd numbers is 3. Why? Because any set of consecutive odd numbers will include multiples of 3, ensuring that the sum will be divisible by 3. So, like, 3 is the magic number here.
4-12n=-7 -12n=-7-4 -12n=-11 12n=11 n=11/12 n=0.916666666666666666...
Im not sure if this is -12n or just 12n so I will give you both: -12n -19=77 n= -8 12n-19=77 n=8