The highest common factor (HCF) of 60 and 108 is the largest positive integer that divides both 60 and 108 without leaving a remainder. To find the HCF, we need to factorize both numbers into their prime factors. The prime factorization of 60 is 2^2 * 3 * 5, and the prime factorization of 108 is 2^2 * 3^3. The common factors between 60 and 108 are 2^2 and 3, so the HCF is 2^2 * 3, which equals 12.
It is: 12
The GCF is 10.
The GCF/HCF of 108 and 192 is 12.
HCF is the highest common factor of two or more numbers. One such pair which has 60 as their HCF can be: 120 and 180.
36It is: 36
It is 12
124
27 and 108 respectively
The HCF of the numbers 540 and 108 is 108.
It is 36
It is: 12
27
4
It is: 12
It is 12
The HCF of 108 and 336 is 12
The HCF of 12 and 60 is 12