288
1440
288
To find an LCD, you need to have at least two denominators.
288
It is 8
288
1440
288
3/4 = 9/12 so LCD is 12.
288
K/3 + k/4 = 1 LCD=12 *divide lcd by denominator* K(4) + K(3) = 12(1) 4k + 3k = 12 7k = 12 k=12/7
8
28
Assume an additive expression.X5 + X3X3(X2 + 1)--------------------so,X3====Is the LCD
To find an LCD, you need to have at least two denominators.
12