Q: What is the LCD of 3 over 8 and 1 over 4?

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K/3 + k/4 = 1 LCD=12 *divide lcd by denominator* K(4) + K(3) = 12(1) 4k + 3k = 12 7k = 12 k=12/7

The LCD of 3/4 and 4/5 is 20.

28 is the LCD

5 1/4. LCD=4 3 1/2 + 1 3/4 3 2/4 + 1 3/4 4 5/4 5 1/4

LCD(3, 5, 4, 2) = 60

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3/4 = 9/12 so LCD is 12.

288

K/3 + k/4 = 1 LCD=12 *divide lcd by denominator* K(4) + K(3) = 12(1) 4k + 3k = 12 7k = 12 k=12/7

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28

Assume an additive expression.X5 + X3X3(X2 + 1)--------------------so,X3====Is the LCD

To find an LCD, you need to have at least two denominators.

12