K/3 + k/4 = 1 LCD=12 *divide lcd by denominator* K(4) + K(3) = 12(1) 4k + 3k = 12 7k = 12 k=12/7
The LCD of 3/4 and 4/5 is 20.
28 is the LCD
5 1/4. LCD=4 3 1/2 + 1 3/4 3 2/4 + 1 3/4 4 5/4 5 1/4
LCD(3, 5, 4, 2) = 60
12
288
1440
288
3/4 = 9/12 so LCD is 12.
288
K/3 + k/4 = 1 LCD=12 *divide lcd by denominator* K(4) + K(3) = 12(1) 4k + 3k = 12 7k = 12 k=12/7
8
28
Assume an additive expression.X5 + X3X3(X2 + 1)--------------------so,X3====Is the LCD
12
To find an LCD, you need to have at least two denominators.