The answer depends on whether or not a is a factor of c.
The GCF is b.
(a - c)(b - d)
The factors of 3a are 3 and a. The factors of 6c are 6 and c. The factors of ab are a and b.
(a+b)(a squared-ab+b squared)
You want: abc + ab Factor out the common terms which are "a" and "b" ab ( c + 1 )
ab-2ac+b^2-2bc
Factor by grouping. x2y - xyb - abx + ab2 The first two can factor out an xy, so xy(x - b) The second two can factor out a -ab, so -ab(x - b) and we have xy(x - b) - ab(x - b) Since what is inside the parentheses is alike, we can be assured that we have factored correctly and now continue to group: ANS: (x - b)(xy - ab)
The answer depends on whether or not a is a factor of c.
No, A person with AB- can receive from O-, A-, B-, or AB-. See chart on related link. A positive Rh factor can receive from a negative, but not the other way around.
The GCF is b.
(a - 7b)(a + 6b)
Let y= ab+(- a)(b) +(-a)(-b) factor out -a y= ab+(-a){b+(-b)} y=ab+(-a)(0) y =ab -------------------(1) now factor out b y= b{a+(-a)}+(-a)(-b) y= b(0) +(-a)(-b) y= (-a)(-b)-----------------(2) equate (1) and (2) (-a)(-b)=ab minus x minus = positive
The GCF is a.
the (zero-factor property)
My understanding is that the blood type and Rh factor are independently inherited, so that all the combinations are possible: B+, B-, AB+, and AB-
x2y + axy + abx + a2b Factor by grouping. xy(x + a) + ab(x + a) (xy + ab)(x + a)