To find the greatest common factor (GCF) of 18m^2 and 7m, we need to factor both terms. The factors of 18m^2 are 1, 2, 3, 6, 9, 18, m, and m^2. The factors of 7m are 1, 7, m. The common factors between the two terms are 1 and m. Therefore, the GCF of 18m^2 and 7m is 1m, which is equivalent to just m.
7m and 18m2 1m is the GCF
The greatest common factor (GCF) is 7m.
To find the greatest common factor (GCF) of 14m^2 and 21m, we first need to factor each term. The factors of 14m^2 are 1, 2, 7, 14, m, and m. The factors of 21m are 1, 3, 7, 21, m, and 1. The common factors between the two terms are 1, 7, and m. Therefore, the greatest common factor of 14m^2 and 21m is 7m.
7m
7m
7m and 18m2 1m is the GCF
The greatest common factor (GCF) is 7m.
The GCF is m.
If one term is a factor of the other, it is automatically the GCF. 7m is a factor of 14m and the GCF of this problem.
To find the greatest common factor (GCF) of 14m^2 and 21m, we first need to factor each term. The factors of 14m^2 are 1, 2, 7, 14, m, and m. The factors of 21m are 1, 3, 7, 21, m, and 1. The common factors between the two terms are 1, 7, and m. Therefore, the greatest common factor of 14m^2 and 21m is 7m.
The GCF of 44m and 60n is 4.
(10q - 7m)(10q - 7m) or (10q - 7m)2
factor by grouping 7m(m-2)+6n(2-m)
-(4m + 3)(5m - 2)
You can find this by grouping the factors, then looking for common factors:2my + 7x + 7m + 2xy = (2my + 2xy) + (7x + 7m) = 2y(m+x) + 7(m+x).Since the factor m+x also happens to be a common factor, you can use the distributive law once more: 2y(m+x) + 7(m+x) = (2y+7)(m+x).Sometimes you have to try several possibilities; and of course, not all polynomials with 4 or more factors can be factored this way - or at all.
it is prime. it cannot factor out.
7x8=56 ANSWER-56