You can find this by grouping the factors, then looking for common factors:
2my + 7x + 7m + 2xy = (2my + 2xy) + (7x + 7m) = 2y(m+x) + 7(m+x).
Since the factor m+x also happens to be a common factor, you can use the distributive law once more: 2y(m+x) + 7(m+x) = (2y+7)(m+x).
Sometimes you have to try several possibilities; and of course, not all polynomials with 4 or more factors can be factored this way - or at all.
(x+y)2
(x-y)2 is a square so (x-y)2 >= 0 expanding, x2 - 2xy + y2 >= 0 so x2 + y2 >= 2xy or 2xy <= x2 + y2
(x+y)2 = x2 + 2xy + y2
2xy - 4x + 8y - 16 can be factored.(2xy - 4x) + (8y - 16)2x(y - 2) + 8(y - 2)Since y-2 is the same as the other, it would turn out like this:(2x + 8)(y - 2):]
Assuming y' is dy/dx, y = x^4/4 + yx^2
Since 2xy is a factor of 2x2y, it is automatically the GCF.
(x + 5y)(x - 3y)
( 2xy - 4x ) + ( 8y - 16)2 ( xy - 2x ) + 2 ( 4y - 8 ) Answer
The greatest common factor of 4xy and -6xy is 2xy. To find the greatest common factor, we first factor out the numbers 4 and -6 to get 2(2xy) and -2(3xy). The greatest common factor is the highest common factor that divides both terms evenly, which in this case is 2xy.
2xy + 6xy = 8xy
4x2 - 4x + 2xy - 2y = 4x(x - 1) + 2y(x - 1) (4x + 2y)(x - 1).
2(x - 1)(2x + y)
2xy - 4x plus 8y - 16 equals x plus 4 in parentheses multiplied by 2y minus 4 in parentheses. So, the factors are ( x + 4) and ( 2y - 4) .
(3x - y)(x + y)(3x - y)(x + y)
What is : 5xy- x2t + 2xy + 3x2t
The three terms are: -3xy2, 2xy and -4y3
2xy + 4x + 8y + 16 = 2[xy + 2x + 4y + 8] = 2[x(y + 2) + 4(y + 2)] = 2(y + 2)(x + 4)