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You can find this by grouping the factors, then looking for common factors:
2my + 7x + 7m + 2xy = (2my + 2xy) + (7x + 7m) = 2y(m+x) + 7(m+x).
Since the factor m+x also happens to be a common factor, you can use the distributive law once more: 2y(m+x) + 7(m+x) = (2y+7)(m+x).
Sometimes you have to try several possibilities; and of course, not all polynomials with 4 or more factors can be factored this way - or at all.
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What is x squared plus 2xy plus y squared?
(x+y)2
Prove '2xy is less than equal to x square plus y square'?
(x-y)2 is a square so (x-y)2 >= 0 expanding, x2 - 2xy + y2 >= 0 so x2 + y2 >= 2xy or 2xy <= x2 + y2
X plus y squared?
(x+y)2 = x2 + 2xy + y2
2xy - 4x plus 8y - 16?
2xy - 4x + 8y - 16 can be factored.(2xy - 4x) + (8y - 16)2x(y - 2) + 8(y - 2)Since y-2 is the same as the other, it would turn out like this:(2x + 8)(y - 2):]
If Y' equals 2xy plus x to power 3 what is y equal to?
Assuming y' is dy/dx, y = x^4/4 + yx^2
