6y(1) & 6y(3)
The answer is 6y
The GCF is 6y
You take out the common factor, 6. 6y + 18 = 6(y + 3)
6x-6y=6(x-y) The factors of 6(x-y) are 6 and (x-y).
(2y + 3)(4y2 - 6y +9)
It is: (6y+1)(y-5) when factored
The GCF is 1.
The GCF is 6y
To factor the expression (6y + 12), first, identify the greatest common factor (GCF) of the terms, which is 6. Factor out the GCF: [ 6y + 12 = 6(y + 2). ] Thus, the factored form of the expression is (6(y + 2)).
3
-6y + 14 + 4y = 32-2y = 32 - 14-2y = 18y = - 9
You take out the common factor, 6. 6y + 18 = 6(y + 3)
To solve the equation (-3(6y - 7) + 10 = 8), first distribute (-3) to both terms inside the parentheses: (-18y + 21 + 10 = 8). Combine like terms: (-18y + 31 = 8). Next, subtract 31 from both sides: (-18y = 8 - 31) which simplifies to (-18y = -23). Finally, divide by (-18) to find (y = \frac{23}{18}).
The greatest common multiple of any set of integers is infinite.
2X + 6Y = 12 3X + 9Y = 18 try elimination - 3(2X + 6Y = 12) 2(3X + 9Y = 18) - 6X - 18Y = - 36 6X + 18Y = 36 ================= I will say this system is dependent and an infinite number of solutions can be found.
Pull out the common factor of 2 ... 2(y^2+6y-16) Then just factor (y^2+6y-16) ... (y-2)(y+8)
Prime factor both numbers or expressions and use the factors the number of times it was used the MOST in either number. 6y^3=2*3*y*y*y 18y^4=2*3*3*y*y*y*y 2*3*3*y*y*y*y=18y^4
(6y + 1)(6y - 1)