The GCF is 1.
6y(1) & 6y(3) The answer is 6y
The GCF is 6y
3
You take out the common factor, 6. 6y + 18 = 6(y + 3)
The greatest common multiple of any set of integers is infinite.
Pull out the common factor of 2 ... 2(y^2+6y-16) Then just factor (y^2+6y-16) ... (y-2)(y+8)
(6y + 1)(6y - 1)
25x2 - 36y2 = ( 5x + 6y ) ( 5x - 6y )
11
The divisors of 108 are: 1, 2, 3, 4, 6, 9, 12, 18, 27, 36, 54, 108.
x(y - 10) + 6y
Oh, dude, it's like super easy. So, you can factor out the greatest common factor, which in this case is 3. So, you get 3(2y + 3). And that's it, you're done! Math problem solved, like, no big deal.