Let the number be x:-
12+x < 30
It is not possible to answer the question since the inequality symbol cannot be viewed.
0 - 9 plus A - F
Twice a number increased by eight is greater than negative four.
2 < 2x + 4 < 18 Subtract 4: -2 < 2x < 14 Divide by 2: -1 < x < 7
A plus number.
This compound inequality cannot be solved.
You need to reverse the inequality symbol when multiplying both sides of an inequality by a negative number because you are changing the sign of both sides of the equation. Since inequality, such as "less than", means "to the left of" on the number line (where left is minus and right is plus) then a number that is less than another will be greater than the other if the signs were reversed. Example: 3 is less than 4, but -3 is greater than -4.
It is an inequality in x.
Yes
A number is called a "solution" for an inequality if, when you plug that number into the variable, the inequality becomes true. For example, 4 is a solution to the inequality "x + 5 < 10", because when you plug in 4 for x, you get "4 + 5 < 10", which is true. (4 plus 5 is 9, which is less than 10.) On the other hand, 6 is not a solution to the inequality "x + 5 < 10", because when you plug in 6 for x, you get "6 + 5 < 10", which is false. (6 plus 5 is 11, which isn't less than 10.)
8
The answer is x < 0.5
25
x < 2/3
It is the inequality: N + 2 <= 1.
Do you mean 3 + 4|3x + 7| ≤ - 89? There is no solution to the inequality, since it is a false statement. A positive number cannot be equal or less than a negative number. On the left side, you are dealing only with positive numbers, since the absolute value is always positive, no matter what the values of x are.
6x + 7 < 3x + 106x - 3x