the largest 6 digit number is 999999 however following the rules provided, the largest number would be 789643.
23 or 41
If the sum of digits of a number is a multiple of 3 then it is divisible by 3. Sum of digits of 234567 = 2+3+4+5+6+7 = 27 = 3x9 So, 234567 is not a prime number because it is divisible by 3.
37
If you multiply two prime numbers, the product (result) will be a composite number, not a prime number. A prime number has exactly two factors, 1 and itself. The product of two prime numbers will have those two numbers as factors, as well. The sum of two prime numbers might be prime if one of those two numbers is 2, the only even prime number, but otherwise it will not be a prime because two odd numbers will have an even sum, which means it is divisible by 2. Examples: 2 + 3 = 5 (prime) 3 + 7 = 10 (not prime) 13 + 17 = 30 (not prime) If you multiply two prime numbers, the sum of the digits of the product might or might not be prime. Examples: 2 x 7 = 14, sum of digits is 5 (prime) 2 x 11 = 22, sum of digits is 4 (not prime) 3 x 5 = 15, sum of digits is 6 (not prime) 3 x 7 = 21, sum of digits is 3 (prime) 5 x 7 = 35, sum of digits is 8 (prime)
largest prime no. 6-bit is 61.
987654
987654
543210
Answer: 999999
999983
99990
987653
4
I suspect that it is 6^940 which is 731 digits long. The largest through reordering the digits is only 9640.
963 3 is the prime 6/3=2 9/3=3 :)
the largest 6 digit number is 999999 however following the rules provided, the largest number would be 789643.