37
36
Prime number between 196 and 289 whose digits add to 14? Possibles 239, 248, 257, 266, 275, 284. 248, 266 and 284 are multiples of 2, 275 is a multiple of 5. This leaves 239 and 257. Only 239 has one digit which is the square of another. So there you have it.
Square them both, find a non-square integer between those two results, and then take the square root of that number. In other words, find a non-square integer between 25 and 49, and since there is only one square number between them, 36, that should be easy; let's pick 42, and then take the square root of it. Ta da! √42 is an irrational number between 5 and 7, its first 30 digits being 6.48074069840786023096596743608.
9
81
36
144
36=6*6=2*18=9*4.
There can't be a prime number that has a square root because the square root would be a factor of the number.
Such a number does not exist. 3600 is 60 squared and 4900 is 70 squared There is no number between 60 and 70 that is a multiple of 15 so there can be no square between 3600 and 4900 that is a multiple of 15.
289
The number nine is a composite number (3 x 3 = 9) and it is a square number (32 = 9). It is a divisor of any number that has digits having the sum of nine or a multiple of 9 (For example, the digits in 367,218 add up to 27, which is a multiple of 9, and the digits in 27 also add up to 9)
144
64
4225
The number of digits in the square root of a number depends on the number. If it is a square number, the square root will have a finite number of digits. If the number is not a square number then the square root will be an irrational number with an infinite, non-repeating decimal representation. In both cases, the number of digits before the decimal point, in the square root of x will be the rounded value of 1+0.5*log10(x)
I cannot see how odd or even will determine the number of digits in the square root. For example:100 is an even number, and its square root is 10 (2 digits)121 is an odd number, and its square root is 11 (2 digits)Maybe the question is not phrased properly for what the questioner is asking.