Alright, buckle up, buttercup. To find the least common multiple of 10ab and 14abc, you need to break down both numbers into their prime factors. The prime factors of 10ab are 2 * 5 * a * b, while the prime factors of 14abc are 2 * 7 * a * b * c. Now, the least common multiple will be the product of all the unique prime factors with the highest power they appear in either number. So, the least common multiple of 10ab and 14abc is 2 * 5 * 7 * a * b * c. Hope that clears things up for ya!
10ab + 15b = 5b (2a + 3)
7
No.
10ab
Oh, dude, factorizing 5A + 10AB is like breaking down a complicated relationship. You just gotta find the common factor between the terms, which in this case is 5A. So, you can rewrite it as 5A(1 + 2B). It's like simplifying drama in your life, one step at a time.
What is The simplified form of (3a2 - 5ab plus c2) plus (-2a2 plus 10ab plus 6c2)
5a(a+2b+b²)
That's not really enough information to be able to solve it...
2a x 3b = 6ab
This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a
It depends on the chemical reaction between substance A and substance B. The stoichiometry of the reaction will determine the amount of product formed. You would need to balance the chemical equation to calculate the exact amount of product formed.
Oh, what a happy little math problem we have here! To solve 2a x 5b, we simply multiply the numbers together. So, the answer is 10ab. Just like blending colors on our canvas, we're combining terms in a beautiful way. Great job exploring the world of math today!