70abc
10ab
10ab + 15b = 5b (2a + 3)
7
5a(2b + 1)
No.
What is The simplified form of (3a2 - 5ab plus c2) plus (-2a2 plus 10ab plus 6c2)
5a(a+2b+b²)
That's not really enough information to be able to solve it...
1ab
5a+10b = 10ab
2a x 3b = 6ab
This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a