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Q: How do you factorise 5A plus 10AB?

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15

This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a

10ab + 15b = 5b (2a + 3)

2a + 5a + 3a = 10a

5a + 20 = ? Your question is incomplete.

Related questions

5a(a+2b+b²)

10ab

a(5+b)

15

This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a

10ab + 15b = 5b (2a + 3)

What is The simplified form of (3a2 - 5ab plus c2) plus (-2a2 plus 10ab plus 6c2)

2a + 3a = 5a

5a+10b = 10ab

5a

5a + 3 + (2a - 2) + a= 5a + 3 + 2a - 2 + a= 8a + 1

2a + 5a + 3a = 10a

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