15
This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a
10ab + 15b = 5b (2a + 3)
2a + 5a + 3a = 10a
5a + 20 = ? Your question is incomplete.
5a(a+2b+b²)
10ab
15
This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a
10ab + 15b = 5b (2a + 3)
What is The simplified form of (3a2 - 5ab plus c2) plus (-2a2 plus 10ab plus 6c2)
5a + 3 + (2a - 2) + a= 5a + 3 + 2a - 2 + a= 8a + 1
5a
2a + 5a + 3a = 10a
2a+5a+9a = 16a
The statement is false. 5a +6 = 5a + 30 Subtract 5a from both sides: 6 = 30 and that is plain and simple rubbish!
5a + 20 = ? Your question is incomplete.